πŸ“‹ IB Content Statements (S3.1)

This topic covers the following syllabus points from the IB Chemistry 2025 guide:

  • S3.1.1: The periodic table is arranged into groups and periods. Elements in a group have the same number of valence electrons.
  • S3.1.2: Trends in properties across a period and down a group can be explained by the concepts of nuclear charge, electron shielding, and atomic/ionic radius.
  • S3.1.3: Trends in metallic/non-metallic character, ionization energy, electron affinity, and electronegativity can be explained by the same concepts.
  • S3.1.4: Oxides of Period 3 change character from basic (metal oxides) through amphoteric ($Al_2O_3$) to acidic (non-metal oxides).

HL Extension

  • S3.1.5 (HL): First ionization energy data for successive elements across a period provides evidence for sub-shells.
  • S3.1.6 (HL): Transition metals show variable oxidation states, form complex ions, and form colored compounds.

πŸ“ Atomic & Ionic Radius

Trend Direction Explanation
Across a period Radius decreases β†’ $Z_{eff}$ increases (more protons, same shielding), so electrons are pulled closer to the nucleus.
Down a group Radius increases ↓ More electron shells are added, increasing the distance. Increased shielding also reduces the pull on valence electrons.

Ionic Radius Rules

  • Cations are smaller than their parent atoms (lost electrons β†’ fewer shells or reduced repulsion, remaining electrons pulled in tighter).
  • Anions are larger than their parent atoms (gained electrons β†’ more repulsion, electron cloud expands).
  • Isoelectronic species (same number of electrons): more protons = smaller radius. E.g., $O^{2-} > F^- > Na^+ > Mg^{2+} > Al^{3+}$ (all have 10 electrons).

⚑ Ionization Energy

Definition

The first ionization energy ($IE_1$) is the minimum energy needed to remove one mole of electrons from one mole of gaseous atoms to form one mole of gaseous $1+$ ions.

$$X(g) \rightarrow X^+(g) + e^-$$

Trend Direction Explanation
Across a period IE increases β†’ $Z_{eff}$ increases, electrons are more tightly held. Smaller atomic radius means electrons are closer to the nucleus.
Down a group IE decreases ↓ More shells β†’ more distance and shielding β†’ valence electrons are easier to remove.

HL: Anomalies in IE across Period 2 & 3

Two "dips" in the otherwise increasing trend:

  1. Group 2 β†’ Group 13 dip: $Be β†’ B$ (or $Mg β†’ Al$). Group 13 loses a $2p$ electron (higher energy, further from nucleus) vs a $2s$ electron in Group 2 β†’ easier to remove.
  2. Group 15 β†’ Group 16 dip: $N β†’ O$ (or $P β†’ S$). Group 16 has a paired electron in one $p$-orbital. Electron-electron repulsion in the pair makes it easier to remove.

🧲 Electronegativity

Definition

Electronegativity ($\chi$) is the ability of an atom in a covalent bond to attract the shared pair of electrons towards itself.

Measured on the Pauling scale: Fluorine = 4.0 (most electronegative), Francium is the least.

Trend Direction Explanation
Across a period EN increases β†’ Smaller radius + higher $Z_{eff}$ β†’ stronger pull on shared electrons.
Down a group EN decreases ↓ Larger radius + more shielding β†’ weaker pull on shared electrons.

Noble gases have no electronegativity values because they do not normally form covalent bonds. Don't include them in trend discussions.

πŸ§ͺ Period 3 Oxides

The oxides of Period 3 show a clear transition from basic to acidic character:

Element Oxide Bonding Character pH of solution
$Na$ $Na_2O$ Ionic Strongly basic ~14
$Mg$ $MgO$ Ionic Basic ~9
$Al$ $Al_2O_3$ Ionic with covalent character Amphoteric Insoluble
$Si$ $SiO_2$ Giant covalent Weakly acidic Insoluble
$P$ $P_4O_{10}$ Simple covalent Acidic ~1
$S$ $SO_3$ Simple covalent Strongly acidic ~1
$Cl$ $Cl_2O_7$ Simple covalent Strongly acidic ~1
pH gradient bar chart showing Period 3 oxides from basic to acidic

Why the change?

Metal oxides contain oxide ions ($O^{2-}$) which act as bases in water: $O^{2-} + H_2O \rightarrow 2OH^-$

Non-metal oxides form acids when dissolved in water: $SO_3 + H_2O \rightarrow H_2SO_4$

$Al_2O_3$ is amphoteric β€” it can react with both acids AND bases.

🧠 Memory Aids

πŸ”€ "ENS" β€” Three factors for ALL trends

  • Effective nuclear charge ($Z_{eff}$)
  • Number of electron shells
  • Shielding (by inner electrons)

Every single periodic trend answer uses these three factors.

πŸ”€ Across a Period β€” "SIR" (Small, Ionize, Reactive non-metals)

  • Smaller atomic radius
  • Increased IE and EN
  • Rising non-metallic character

πŸ”€ Cations vs Anions β€” "Cats are small, Ans are large"

Cations (positive) are smaller than the parent atom. Anions (negative) are larger. Cat = small domestic animal. An(aconda) = large animal.

πŸ”€ Period 3 Oxides β€” "BAA" (Basic β†’ Amphoteric β†’ Acidic)

Reading from left to right across Period 3 oxides: Basic metals β†’ Amphoteric (aluminium) β†’ Acidic non-metals. Like a sheep: "BAA" πŸ‘

πŸ”€ HL IE Anomalies β€” "2p then Pair"

Two dips: (1) Losing a 2p electron is easier than 2s β†’ Gp 2β†’13 dip. (2) A paired electron is easier to remove than unpaired β†’ Gp 15β†’16 dip.

🌍 Real-World Applications

πŸ”₯ Alkali Metals in Water β€” Group 1 Reactivity

Context: Sodium, potassium, and cesium react increasingly vigorously with water, from fizzing (Na) to explosive (Cs).

Science: Down Group 1, IE decreases because the valence electron is further from the nucleus with more shielding. This means the electron is lost more easily β†’ faster, more vigorous reaction.

Impact: This trend is used to predict reactivity of any group in the periodic table. Metals get more reactive going down; non-metals get more reactive going up.

🏭 Acid Rain β€” Non-Metal Oxides

Context: Burning fossil fuels releases sulfur dioxide ($SO_2$) and nitrogen oxides ($NO_x$), which dissolve in rainwater to form sulfuric and nitric acid.

Science: These are non-metal oxides β†’ acidic when dissolved in water. $SO_2 + H_2O \rightarrow H_2SO_3$ and $2SO_2 + O_2 \rightarrow 2SO_3$, $SO_3 + H_2O \rightarrow H_2SO_4$

Impact: Acid rain damages buildings (especially limestone: $CaCO_3 + H_2SO_4 \rightarrow CaSO_4 + H_2O + CO_2$), kills aquatic life, and destroys forests.

🦷 Fluorine in Toothpaste β€” Highest Electronegativity

Context: Fluoride ions ($F^-$) in toothpaste replace hydroxide ions in tooth enamel to form fluorapatite.

Science: Fluorine has the highest electronegativity (4.0) due to its small atomic radius and high nuclear charge. The resulting $F^-$ ion forms very strong ionic bonds in the enamel lattice.

Impact: Fluorapatite is more resistant to acid attack than hydroxyapatite, reducing tooth decay. The strong bonding of $F^-$ is a direct consequence of fluorine's electronegativity.

⚠️ Common Mistakes

  • ❌ "Nuclear charge increases down a group, so IE increases" β†’ βœ… True that nuclear charge increases, but shielding and distance increase more β†’ IE decreases. Always mention all three factors (ENS).
  • ❌ "Atomic radius increases across a period" β†’ βœ… It decreases across a period. More protons with same shielding β†’ electrons pulled closer.
  • ❌ Confusing electronegativity with electron affinity β†’ βœ… Electronegativity is the ability to attract shared electrons in a bond. Electron affinity is the energy change when an atom gains an electron.
  • ❌ "Alβ‚‚O₃ is acidic because aluminium is a metal" β†’ βœ… $Al_2O_3$ is amphoteric β€” it reacts with both acids and bases. This is a key exam point.
  • ❌ Saying noble gases have low electronegativity β†’ βœ… Noble gases have no electronegativity values because they do not form covalent bonds (usually). Do not plot them on EN trend graphs.

πŸ“ Exam-Style Questions

Question 1: Explain the trend in first ionization energy across Period 3. [3 marks]

Mark Scheme:

  • [1 mark] General increase across the period.
  • [1 mark] Nuclear charge / number of protons increases across the period.
  • [1 mark] Shielding remains approximately constant (same number of inner shells) β†’ greater effective nuclear charge β†’ electrons held more tightly.
Question 2: Explain why the atomic radius of sodium is larger than the atomic radius of chlorine. [2 marks]

Mark Scheme:

  • [1 mark] Chlorine has more protons (17 vs 11), creating a greater nuclear charge.
  • [1 mark] With similar shielding (both have 2 inner shells), the valence electrons in Cl are pulled closer to the nucleus.
Question 3: Explain why $Na_2O$ is basic while $SO_3$ is acidic. [3 marks]

Mark Scheme:

  • [1 mark] $Na_2O$ contains $O^{2-}$ ions which react with water: $O^{2-} + H_2O β†’ 2OH^-$ (producing hydroxide ions).
  • [1 mark] $SO_3$ reacts with water to form sulfuric acid: $SO_3 + H_2O β†’ H_2SO_4$.
  • [1 mark] Metal oxides are basic; non-metal oxides are acidic.
Question 4: Rank the following in order of increasing radius: $Na^+$, $F^-$, $Ne$, $Mg^{2+}$. [2 marks]

Mark Scheme:

  • [1 mark] All are isoelectronic (10 electrons).
  • [1 mark] Order: $Mg^{2+} < Na^+ < Ne < F^-$. More protons=smaller radius (tighter pull on the same number of electrons).
Question 5: Explain why fluorine has the highest electronegativity. [2 marks]

Mark Scheme:

  • [1 mark] Very small atomic radius.
  • [1 mark] High nuclear charge relative to its size β†’ bonding electrons are strongly attracted to the nucleus.
Question 6 (HL): Explain the decrease in first ionization energy from nitrogen to oxygen. [2 marks]

Mark Scheme:

  • [1 mark] Oxygen has a paired electron in one of its $2p$ orbitals.
  • [1 mark] Electron-electron repulsion in the pair makes this electron easier to remove than an unpaired electron in nitrogen's half-filled $2p$ subshell.
Question 7: State what is meant by "amphoteric" and give one example. [2 marks]

Mark Scheme:

  • [1 mark] Amphoteric means a substance can react with both acids and bases.
  • [1 mark] Example: $Al_2O_3$ (aluminium oxide).
Question 8: Explain why a chloride ion ($Cl^-$) is larger than a chlorine atom ($Cl$). [2 marks]

Mark Scheme:

  • [1 mark] $Cl^-$ has gained one electron β†’ 18 electrons but only 17 protons.
  • [1 mark] Greater electron-electron repulsion β†’ electron cloud expands β†’ larger radius.